Integrand size = 14, antiderivative size = 14 \[ \int \frac {1}{a+b \tan \left (c+d x^2\right )} \, dx=\text {Int}\left (\frac {1}{a+b \tan \left (c+d x^2\right )},x\right ) \]
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Not integrable
Time = 0.01 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {1}{a+b \tan \left (c+d x^2\right )} \, dx=\int \frac {1}{a+b \tan \left (c+d x^2\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{a+b \tan \left (c+d x^2\right )} \, dx \\ \end{align*}
Not integrable
Time = 1.41 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.14 \[ \int \frac {1}{a+b \tan \left (c+d x^2\right )} \, dx=\int \frac {1}{a+b \tan \left (c+d x^2\right )} \, dx \]
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Not integrable
Time = 0.13 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.00
\[\int \frac {1}{a +b \tan \left (d \,x^{2}+c \right )}d x\]
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Not integrable
Time = 0.24 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.14 \[ \int \frac {1}{a+b \tan \left (c+d x^2\right )} \, dx=\int { \frac {1}{b \tan \left (d x^{2} + c\right ) + a} \,d x } \]
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Not integrable
Time = 0.29 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.00 \[ \int \frac {1}{a+b \tan \left (c+d x^2\right )} \, dx=\int \frac {1}{a + b \tan {\left (c + d x^{2} \right )}}\, dx \]
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Not integrable
Time = 0.44 (sec) , antiderivative size = 187, normalized size of antiderivative = 13.36 \[ \int \frac {1}{a+b \tan \left (c+d x^2\right )} \, dx=\int { \frac {1}{b \tan \left (d x^{2} + c\right ) + a} \,d x } \]
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Not integrable
Time = 0.36 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.14 \[ \int \frac {1}{a+b \tan \left (c+d x^2\right )} \, dx=\int { \frac {1}{b \tan \left (d x^{2} + c\right ) + a} \,d x } \]
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Not integrable
Time = 3.56 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.14 \[ \int \frac {1}{a+b \tan \left (c+d x^2\right )} \, dx=\int \frac {1}{a+b\,\mathrm {tan}\left (d\,x^2+c\right )} \,d x \]
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